Just tried the same burn again. Same Layer Break positions list. Chose the same position, ending in the same result ; error message and burn failure.
It is curious that the "Invalid Address for Write" is very close to the layer break option that I chose. Not exact, but close. I'll put the images up to
see. As I'm posting now, I'm trying a 3rd time, but chose a LB position
at an earlier point, to see how that goes.
I noted earlier that this point of write failure, is right on the edge of something I read in the ImageBurn's log. That was something to do
with LO (is that layer One?).....and the point determined to be reached
when the maximum data was burned, to layer one.....my guess.
Bad wording, but I hope to include that in one of the images. If it's not there, I'll get it from current ImageBurn log going on right now.
If I get that right, it would seem that this LBrk position that failed twice comes right on the edge of the data capacity for layer one, and might be a problem.
Still confused. I could be way off the mark, but just thinking about it.
**See the break position I chose. It's the highest value of them all, and
that sector(?) area is very close to where the process will be, when
the max. data is burned to layer one, if I read that earlier log correctly.
Just curious, cutting close? I hope to attach an image to go with my
ideas now, but may have to come later.
If I'm completely off-track, then how can I determine why the two
burn failures? I tried Nero Speed Disc (name?) , but it's not going to read
the disc for burn errors, is it? Actually, I dont think Nero could even view
the disc, since it couldn't be finalized by ImageBurn.
Second image does not show exactly what I'm looking for, but it
does show where I chose an earlier LB position. At this point only
about 1hr.32min of data is written, whereas in the previous option,
nearly 1hr. 48mins was to be written, before the chosen break point
was reached. So, is that bottom, latter choice pushing it as far as how
much movie could be fit onto the first layer?