Well, fellows i think that "1411200 b/sec is not quite correct number...
We talking about AUDIO CD bit rate. The PCM audio tracks have constant bitrate. That bitrate actualy defines the size of the cd medium converted from lenght in min (74 or 80) to bytes capacity.As you know cd audio players reads cd tracks on 1x speed. First speed is very close somewhere near 150 Kbytes/sec.Thats not just my words, but as i know a international auido standarts! What i really mean? Let`s see:
1x=~(150 kbytes/s)1024= (153600 bytes/sec)60=(9216000 bytes/min)*80 min=((737280000)/(1024))/1024= 703,125 Mbytes total cd space, like we expected ,right?
I`m not so sure about yours calculations:
"""16 bit * 44.1 kHz * 2 channels = 1411200 bits/sec""", because,
(1411200 bits/sec)/8= (176400 bytes/sec)60sec=(10584000 bytes/min)80min=((846720000 bytes)/1024)/1024=807,49 Mbytes total cd space. WOW!
Quite big contradiction,don
t you think!??!?!??!!?! :)))))))))))s do math again: 4772 sec*153600 kbyte/s=732979200 bytes= 699 mb + 1 mb file system =700 mb finaly burned to audio CD.
I made a experiment with 30 audio (WMA) files with total lenght of 4772 sec.They perfectly fit on 703 mb cd as AUDIO PCM format.Let
If your theory (1411200 bits/s) is right , it will newer happen.You do the math by yourself with your constant like me (^).
Therefore, bitrate of PCM AUDIO CD TRACK is 703mb/80min=149,9~150 kbytes/sec or FINALY (150*1024)*8=1228800 BITS/SEC.